Freie Energie Maschine
29.09.2006 um 10:03@geronimo
hast du dir das mal durchgelesen?
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I,Joseph
Newman, have repeatedly stated that mass means NOTHING if it does not have aMECHANICAL
UNDERSTANDING . The equation for horsepower of rotating motor shaft soPROVES - "ft. lbs
X rpm divided by 5252 = HP". Yet that equation does not designatethe TIME of said
horsepower. Constant of mass - rpm implies horsepower per minute.
James Watt in
the late 1700s who established the HP as a unit of measurementspecifically stated that
such a measurement was dependent upon TIME: "33,000 lbs 1 ft.per MINUTE."
Accordingly, the HP of a rotating shaft must be measured in HPper minute of rotating
shaft or, in shorthand, HP of rotating shaft per SECOND. ["550lbs 1 ft. per second."]
I show you now a simple MECHANICAL explanation of HPper second of TRUTH: Take a
shaft and attach it to the center of 1 ft radius [2 ft.diameter] pulley. Now imagine
that you rotate the shaft of one full rotation of 360degrees in one SECOND. Then "you"
have lifted 550 lbs 6.283 ft in one second! ["1 ft.radius gives 6.283 ft in
circumference"] That is, 6.283 HP per second! Per rotation ofshaft! Multiply by [60 rpm]
60 SECONDS that is 376.98 HP per MINUTE!
Saidabove is WRONG! Vague conventional
HP equation gives only 6.283 HP per MINUTE!
The TRUTH of MECHANICAL explanation
given by me has been applied to rotating shaftof 400 lb magnetic rotary of my
revolutionary motor that will shock the world in theimmediate future. IT WILL PROVE WHO
IS THE MASTER OF MY REVOLUTIONARY ENERGYINVENTION!
Fact: Conventional equation
must be changed to the following:
HP of rotating shaft of motor:
HP =
ft lbs X RPM divided by 5252 X 60 =HP per MINUTE.
-------------------------
aha, alles klar, Leistung proMinute ;-) Da hat jemand in der Schule ganz, ganz
fest geschlafen ;-)
hast du dir das mal durchgelesen?
-------------
I,Joseph
Newman, have repeatedly stated that mass means NOTHING if it does not have aMECHANICAL
UNDERSTANDING . The equation for horsepower of rotating motor shaft soPROVES - "ft. lbs
X rpm divided by 5252 = HP". Yet that equation does not designatethe TIME of said
horsepower. Constant of mass - rpm implies horsepower per minute.
James Watt in
the late 1700s who established the HP as a unit of measurementspecifically stated that
such a measurement was dependent upon TIME: "33,000 lbs 1 ft.per MINUTE."
Accordingly, the HP of a rotating shaft must be measured in HPper minute of rotating
shaft or, in shorthand, HP of rotating shaft per SECOND. ["550lbs 1 ft. per second."]
I show you now a simple MECHANICAL explanation of HPper second of TRUTH: Take a
shaft and attach it to the center of 1 ft radius [2 ft.diameter] pulley. Now imagine
that you rotate the shaft of one full rotation of 360degrees in one SECOND. Then "you"
have lifted 550 lbs 6.283 ft in one second! ["1 ft.radius gives 6.283 ft in
circumference"] That is, 6.283 HP per second! Per rotation ofshaft! Multiply by [60 rpm]
60 SECONDS that is 376.98 HP per MINUTE!
Saidabove is WRONG! Vague conventional
HP equation gives only 6.283 HP per MINUTE!
The TRUTH of MECHANICAL explanation
given by me has been applied to rotating shaftof 400 lb magnetic rotary of my
revolutionary motor that will shock the world in theimmediate future. IT WILL PROVE WHO
IS THE MASTER OF MY REVOLUTIONARY ENERGYINVENTION!
Fact: Conventional equation
must be changed to the following:
HP of rotating shaft of motor:
HP =
ft lbs X RPM divided by 5252 X 60 =HP per MINUTE.
-------------------------
aha, alles klar, Leistung proMinute ;-) Da hat jemand in der Schule ganz, ganz
fest geschlafen ;-)